Two electrons are moving in orbits of two hydrogen-like atoms with speeds 3 105 m/s and 2.5 105 m/s respectively. If the radii of these orbits are nearly same then the possible order of energy states are respectively.
- 8 and 10
- 10 and 12
- 9 and 8
- 6 and 5
Answer
(4) 6 and 5
Solution
In Bohr's model of a hydrogen-like atom: rn n2Z and vn Zn
Radii equal n12Z1 = n22Z2 Z n2
v Zn n2n = n
n1n2 = v1v2 = 3 1052.5 105 = 65
Only the pair 6 and 5 has this ratio.
Answer: (4)