The energy of an electron in the ground state (n = 1) for He+ ion is -x J, then that for an electron in (n = 2) state for Be3+ ion in J is
- -x
- - x9
- -4x
- - 49x
Answer
(1) -x
Solution
For a hydrogen-like species: En - Z2n2
He+ (Z = 2, n = 1): E - 41 = -4
Be3+ (Z = 4, n = 2): E - 164 = -4
E( Be3+, n = 2) = E(He+, n = 1) = -x J
Answer: (1)