A resistance wire connected in the left gap of a metre bridge balances a 10 resistance in the right gap at a point which divides the bridge wire in the ratio 3:2. If the length of the resistance wire is 1.5 m, then the length of 1 of the resistance wire is :
- 1.0 10-1 m
- 1.5 10-1 m
- 1.5 10-2 m
- 1.0 10-2 m
Answer
(1) 1.0 10-1 m
Solution
Balance condition of metre bridge: RS = l1l2
⇒ R10 = 32
⇒ R = 15
∵ 1.5 m of wire has resistance 15
∴ Length of 1 wire = 1.515 = 0.1 m = 1.0 10-1 m
Answer: (1)