The size of the images of an object, formed by a thin lens are equal when the object is placed at two different positions 8 cm and 24 cm from the lens. The focal length of the lens is cm.
Answer
16
Solution
Equal size at two positions a convex lens giving one real (inverted) and one virtual (erect) image of equal magnification.
For a lens, m = ff + u (u negative)
u = -8 cm: m1 = ff - 8; u = -24 cm: m2 = ff - 24
m1 = -m2 f - 24 = -(f - 8)
2f = 32 f = 16 cm
Answer: 16