Consider light travelling from a medium A to medium B separated by a plane interface. If the light undergoes total internal reflection during its travel from medium A to B and the speed of light in media A and B are 2.4 108 m/s and 2.7 108 m/s, respectively, then the value of critical angle is :
- -1 ( 89 )
- -1 ( 98 )
- -1 ( 3 13 )
- -1 ( 8 17 )
Answer
(4) -1 ( 8 17 )
Solution
C = B A = c/vBc/vA = vAvB
C = 2.4 1082.7 108 = 89
C = 1 - 6481 = 179
C = 8 17, i.e. C = -1 ( 8 17 )
Answer: (4)