A current of 3 amp. flows through the 2 resistor shown in the circuit. The power dissipated in the 5 resistor is [figure]
- 1 watt
- 5 watt
- 4 watt
- 2 watt
Answer
(2) 5 watt
Solution
The 2 resistor, the 4 resistor and the series pair (1 + 5 ) are all connected across the same two points.
p.d. across each branch = 3 2 = 6 V
Current in the 1 –5 branch = 61 + 5 = 1 A
Power in 5 = I2R = 12 5 = 5 W
Answer: (2)