KMnO4 acts as an oxidising agent in acidic medium. 'X' is the difference between the oxidation states of Mn in reactant and product. 'Y' is the number of 'd' electrons present in the brown red precipitate formed at the end of the acetate ion test with neutral ferric chloride. The value of X + Y is .
Answer
10
Solution
In acidic medium:
MnO4- + 8H+ + 5e- Mn2+ + 4H2O
Oxidation state of Mn changes from +7 to +2 ⇒ X = 7 − 2 = 5
Acetate ion test: neutral FeCl3 gives a deep red colour with acetate; on boiling, a brown-red precipitate of basic iron(III) acetate, Fe(OH)2(CH3COO), is formed.
Fe is in +3 state: Fe3+ = [Ar] 3d5 ⇒ Y = 5
∴ X + Y = 5 + 5 = 10
Answer: 10