In which of the following molecules are all the bonds not equal?
- NF3
- ClF3
- BF3
- AlF3
Answer
(2) ClF3
Solution
NF3: 3 bp + 1 lp ⇒ trigonal pyramidal; all three N–F bonds are equivalent.
BF3, AlF3: 3 bp ⇒ trigonal planar; all bonds equal.
ClF3: 3 bp + 2 lp on Cl (sp3d) ⇒ the two lone pairs occupy equatorial positions ∴ T-shaped molecule.
∴ It has one equatorial and two axial Cl–F bonds; the axial bonds are longer than the equatorial bond, so all the bonds are not equal.
Answer: (2)