The electronegativity difference between N and F is greater than that between N and H yet the dipole moment of NH3 (1.5 D) is larger than that of NF3 (0.2 D). This is because
- in NH3 the atomic dipole and bond dipole are in the opposite directions whereas in NF3 these are in the same direction
- in NH3 as well as in NF3 the atomic dipole and bond dipole are in the same direction
- in NH3 the atomic dipole and bond dipole are in the same direction whereas in NF3 these are in opposite directions
- in NH3 as well as in NF3 the atomic dipole and bond dipole are in opposite directions.
Answer
(3) in NH3 the atomic dipole and bond dipole are in the same direction whereas in NF3 these are in opposite directions
Solution
Both NH3 and NF3 are pyramidal with one lone pair on N; the lone pair gives an orbital (atomic) dipole pointing away from N towards the lone pair.
In NH3: N is more electronegative than H, so each N–H bond dipole points towards N, i.e. the resultant of the bond dipoles points in the same direction as the lone-pair dipole.
⇒ The two add up ∴ large dipole moment (1.5 D).
In NF3: F is more electronegative than N, so each N–F bond dipole points away from N towards F, opposite to the lone-pair dipole.
⇒ They partly cancel ∴ small dipole moment (0.2 D).
As per NCERT, the orbital dipole due to the lone pair is in the same direction as the resultant dipole of the N–H bonds in NH3, but opposite to the resultant dipole of the three N–F bonds in NF3.
Answer: (3)