A uniform force of (3 i + j) newton acts on a particle of mass 2 kg. Hence the particle is displaced from position (2 i + k) metre to position (4 i + 3 j - k) metre. The work done by the force on the particle is
- 13 J
- 15 J
- 9 J
- 6 J
Answer
(3) 9 J
Solution
Displacement: s = (4 i + 3 j - k) - (2 i + k)
= 2 i + 3 j - 2 k
Work done: W = F s = (3 i + j) (2 i + 3 j - 2 k)
= 6 + 3 + 0 = 9 J
Answer: (3)