Two spheres A and B of masses m1 and m2 respectively collide. A is at rest initially and B is moving with velocity v along x-axis. After collision B has a velocity v2 in a direction perpendicular to the original direction. The mass A moves after collision in the direction:
- same as that of B
- opposite to that of B
- = -1 ( 12 ) to the x-axis
- = -1 (- 12 ) to the x-axis
Answer
(4) = -1 (- 12 ) to the x-axis
Solution
Let B move along +y after collision and A move with velocity components (vx, vy).
Conservation of momentum along x: m2 v = m1 vx vx = m2 vm1
Along y: 0 = m2 v2 + m1 vy vy = - m2 v2m1
= vyvx = - 12
= -1 (- 12 ) to the x-axis
Answer: (4)