A particle of mass M, starting from rest, undergoes uniform acceleration. If the speed acquired in time T is V, the power delivered to the particle is
- MV2T
- 12 MV2T2
- MV2T2
- 12 MV2T
Answer
(4) 12 MV2T
Solution
By the work–energy theorem, work done in time T:
W = K = 12MV2 - 0
∴ Power delivered over the time T (average power):
P = WT = 12 MV2T
(The instantaneous power at the instant T would be Fv = M VT V = MV2T.)
Answer: (4)