A uniform metal wire of length l has 10 resistance. Now this wire is stretched to a length 2l and then bent to form a perfect circle. The equivalent resistance across any arbitrary diameter of that circle is
- 10
- 5
- 40
- 20
Answer
(1) 10
Solution
On stretching, volume is constant, so R l2:
R' = 10 (2)2 = 40
Across a diameter the circle is two halves of 20 each in parallel:
Req = 20 2020 + 20 = 10
Answer: (1)