The potential energy of a particle moving along x-direction varies as V = Ax2 x + B. The dimensions of A2B are:
- [ M3/2 L1/2 T-3 ]
- [ M1/2LT-3 ]
- [ M2L1/2T-4 ]
- [ ML2 T-4 ]
Answer
(3) [ M2L1/2T-4 ]
Solution
B is added to x [B] = [ L1/2]
[V] = [A][L2][ L1/2] [A] = [ ML2T-2][ L3/2] = [ ML1/2T-2]
[A2][B] = [ M2LT-4][ L1/2]
= [ M2L1/2T-4]
Answer: (3)