Magnetic moment 2.84 B.M. is given by (At. nos. Ni = 28, Ti = 22, Cr = 24, Co = 27)
- Cr2+
- Co2+
- Ni2+
- Ti3+
Answer
(3) Ni2+
Solution
Spin-only magnetic moment: = n(n+2) B.M.
n(n+2) = 2.84 ⇒ n(n+2) 8 ⇒ n = 2
Cr2+: 3d4 ⇒ 4 unpaired
Co2+: 3d7 ⇒ 3 unpaired
Ni2+: 3d8 ⇒ 2 unpaired ⇒ = 8 = 2.83 B.M.
Ti3+: 3d1 ⇒ 1 unpaired
Answer: (3)