A solid sphere of radius 10 cm is rotating about an axis which is at a distance 15 cm from its centre. The radius of gyration about this axis is n cm. The value of n is
Answer
265
Solution
Moment of inertia about a diameter: Icm = 25MR2
By the parallel axis theorem: I = 25MR2 + Md2
Mk2 = M ( 25 102 + 152 )
k2 = 40 + 225 = 265 cm2
k = 265 cm, n = 265
Answer: 265