Suppose there is a uniform circular disc of mass M kg and radius r m shown in figure. The shaded regions are cut out from the disc. The moment of inertia of the remainder about the axis A of the disc is given by x256 M r2. The value of x is . [figure]
Answer
109
Solution
Axis A is the axis of the disc, through its centre O and perpendicular to its plane.
Mass of each cut-out disc (radius r4): m = M (r/4)2r2 = M16
Each cut-out centre is at d = 34r from O. By the parallel axis theorem:
I1 = 12 M16 ( r4 )2 + M16 ( 3r4 )2
= Mr2512 + 9Mr2256 = 19Mr2512
Both cut-outs: 2I1 = 19Mr2256 (the 135 position does not matter for this axis)
I = 12Mr2 - 19256Mr2 = 128 - 19256Mr2 = 109256Mr2
x = 109
Answer: 109