Let a and b be the vectors of the same magnitude such that | a + b| + | a - b|| a + b| - | a - b| = 2 + 1. Then | a + b|2| a|2 is :
- 2 + 2
- 2 + 4 2
- 4 + 2 2
- 1 + 2
Answer
(1) 2 + 2
Solution
Let | a + b| = p, | a - b| = q and | a| = | b| = r.
By componendo–dividendo, p + qp - q = 2 + 1
pq = ( 2 + 1) + 1( 2 + 1) - 1 = 2 + 2 2 = 1 + 2
p2 = (1 + 2)2 q2 = (3 + 2 2) q2
Also p2 + q2 = 2| a|2 + 2| b|2 = 4r2
(4 + 2 2) q2 = 4r2 q2 = 4r24 + 2 2 = 2r22 + 2
p2r2 = 2(3 + 2 2)2 + 2 = 2(3 + 2 2)(2 - 2)2
= 6 - 3 2 + 4 2 - 4 = 2 + 2
Answer: (1)