Let a = i + j + k, b = 3 i + 2 j - k, c = j + k and d be a unit vector such that a d = b d and c d = 1. If c is perpendicular to a, then |3 d + c|2 is equal to
Answer
5
Solution
( a - b) d = 0 d a - b
a - b = -2 i - j + 2 k, | a - b| = 3
d = 13(-2 i - j + 2 k)
c a + = 0 = -
c d = 13(- + 2 ) = 13(-3 ) = = 1
d = 13(2 i + j - 2 k) in both cases, and 2 = 1
3 d = 2 i + j - 2 k
c = j + 2 k = - 2 j + 2 k = - j + k
3 d + c = 2 i - k
|3 d + c|2 = 4 + 1 = 5
Answer: 5