The cylindrical tube of a spray pump has radius R, one end of which has n fine holes, each of radius r. If the speed of the liquid in the tube is V, the speed of the ejection of the liquid through the holes is
- VR2n3r2
- V2Rnr
- VR2n2r2
- VR2nr2
Answer
(4) VR2nr2
Solution
By the equation of continuity, volume flowing in per second = volume flowing out per second.
Let the speed of ejection be v.
R2 V = n( r2)v
∴ v = VR2nr2
Answer: (4)