The amplitude and phase of a wave that is formed by the superposition of two harmonic travelling waves, y1(x, t) = 4 (kx - t) and y2(x, t) = 2 (kx - t + 2 3 ), are: (Take the angular frequency of initial waves same as )
- [ 3, 6 ]
- [2 3, 6 ]
- [6, 2 3 ]
- [6, 3 ]
Answer
(2) [2 3, 6 ]
Solution
Both waves have the same k and ; their phase difference is = 2 3, with A1 = 4 and A2 = 2.
Resultant amplitude: A = A12 + A22 + 2A1A2
A = 16 + 4 + 2(4)(2) (- 12 )
= 12 = 2 3
Phase of the resultant (measured from y1): = A2 A1 + A2
= 2 324 + 2 (- 12 ) = 33 = 1 3
= 6
y = 2 3 (kx - t + 6 ), i.e. [2 3, 6 ]
Answer: (2)