A galvanometer of resistance 100 Ω gives full scale deflection for a current of 1 mA. It is converted into an ammeter of range 0 – 10 A. The shunt required is :
- 0.001 Ω
- 0.10 Ω
- 1.0 Ω
- 0.01 Ω
Answer
(4) 0.01 Ω
Solution
The shunt S is connected in parallel with the galvanometer, so both have the same p.d.
IgG = (I - Ig)S
S = IgGI - Ig = 10-3 10010 - 0.001
S = 0.19.999
S 0.01
Answer: (4)