A 2 amp current is flowing through two different small circular copper coils having radii ratio 1 : 2. The ratio of their respective magnetic moments will be
- 2 : 1
- 4 : 1
- 1 : 4
- 1 : 2
Answer
(3) 1 : 4
Solution
Magnetic moment of a coil: m = IA = I r2
Same current, so m1m2 = r12r22 = ( 12 )2 = 14
Answer: (3)