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JEE Main 2024 (Online) 30th January Evening ShiftMCQEasy📈 Topic in 14% papers+4−1
Ques. 1JEE Main 2024, 30 January (Evening Shift)

If a substance 'A' dissolves in solution of a mixture of 'B' and 'C' with their respective number of moles as nA, nB and nC. Mole fraction of C in the solution is

  1. nCnA nB nC
  2. nBnA+nB
  3. nCnA+nB+nC
  4. nCnA-nB-nC

Answer

(3) nCnA+nB+nC

Solution

Mole fraction = moles of the componenttotal moles of all components

∵ the solution contains A, B and C ⇒ total moles = nA+nB+nC

⇒ C = nCnA+nB+nC

Answer: (3)

Keep practising — Solutions

Ques. 2JEE Main 2024, 29 January (Morning Shift)

The osmotic pressure of a dilute solution is 7 105 Pa at 273 K. Osmotic pressure of the same solution at 283 K is 104 Nm-2.

Ques. 3JEE Main 2024, 29 January (Evening Shift)

Molality of 0.8 M H2SO4 solution (density 1.06 g cm-3) is 10-3 m.

Ques. 4JEE Main 2024, 27 January (Morning Shift)

A solution of two miscible liquids showing negative deviation from Raoult's law will have :

  1. increased vapour pressure, increased boiling point
  2. increased vapour pressure, decreased boiling point
  3. decreased vapour pressure, decreased boiling point
  4. decreased vapour pressure, increased boiling point
Ques. 5JEE Main 2024, 27 January (Evening Shift)

The quantity which changes with temperature is :

  1. Molality
  2. Molarity
  3. Mole fraction
  4. Mass percentage

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