A first order reaction has a specific reaction rate of 10-2 sec-1. How much time will it take for 20 g of the reactant to reduce to 5 g?
- 138.6 sec
- 346.5 sec
- 693.0 sec
- 238.6 sec
Answer
(1) 138.6 sec
Solution
For a first order reaction, t = 2.303k [R]0[R]
t = 2.30310-2 205
= 230.3 4
= 230.3 0.602
= 138.6 sec
(Alternatively: 20 g → 5 g is two half-lives; t1/2 = 0.69310-2 = 69.3 sec ⇒ t = 2 69.3 = 138.6 sec.)
Answer: (1)