What is the activation energy for a reaction if its rate doubles when the temperature is raised from 20 C to 35 C? (R = 8.314 J mol-1 K-1)
- 34.7 kJ mol-1
- 15.1 kJ mol-1
- 342 kJ mol-1
- 269 kJ mol-1
Answer
(1) 34.7 kJ mol-1
Solution
T1 = 293 K, T2 = 308 K, k2k1 = 2
As per NCERT, k2k1 = Ea2.303R ( T2 - T1T1T2 )
⇒ 2 = Ea2.303 8.314 ( 15293 308 )
⇒ Ea = 0.3010 2.303 8.314 293 30815
= 34,695 J mol-1
34.7 kJ mol-1
Answer: (1)