The velocity at which 6 kg mass (shown in figure) strikes the ground when it is released from a height of 6 m above the ground is m/s. Assume pulley is massless and string is light and inextensible. (Take g = 10 m/s2) [figure]
- 7.74
- 7.20
- 6.55
- 4.50
Answer
(1) 7.74
Solution
[figure]
Light string and massless pulley ⇒ same tension T and same acceleration a (6 kg down, 2 kg up)
6 kg: 60-T=6a
2 kg: T-20=2a
Adding: 40=8a ⇒ a=5 m/s2
6 kg block falls s=6 m from rest: v2=0+2as=2 5 6=60
∴ v= 60 7.74 m/s
Answer: (1)