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Differential Equations

JEE Main 2024 (Online) 30th January Evening ShiftNumericalHard📈 Topic in 3% papers+4
Ques. 1JEE Main 2024, 30 January (Evening Shift)

Let Y=Y(X) be a curve lying in the first quadrant such that the area enclosed by the line Y-y=Y (x)(X-x) and the co-ordinate axes, where (x, y) is any point on the curve, is always -y22 Y (x)+1, Y (x) 0. If Y(1)=1, then 12 Y(2) equals .

Answer

20

Solution

[figure]

Tangent at (x, y) meets the axes at (x- yY', 0 ) and (0, y-xY')

Area = 12 (x- yY' )(y-xY')=xy- x2Y'2- y22Y'

=- y22Y'+1 2xy-x2Y'=2

dydx- 2xy=- 2x2 (linear), I.F. =e-2 x= 1x2

yx2= - 2x4dx= 23x3+c

Y(1)=1 c= 13 y= 23x+ x23

Y(2)= 13+ 43= 53 12Y(2)=20

Answer: 20

Keep practising — Differential Equations

Ques. 2JEE Main 2024, 29 January (Morning Shift)

A function y=f(x) satisfies f(x) 2x+ x- (1+ 2x )f'(x)=0 with condition f(0)=0. Then, f ( 2 ) is equal to

  1. 2
  2. 1
  3. -1
  4. 0
Ques. 3JEE Main 2024, 29 January (Morning Shift)

If the solution curve y=y(x) of the differential equation (1+y2 ) (1+ ex )dx+x dy=0, x>0 passes through the point (1,1) and y(e)= - ( 32 ) + ( 32 ), then +2 is .

Ques. 4JEE Main 2024, 29 January (Evening Shift)

If ( yx )= e|x|+ 2 is the solution of the differential equation x ( yx ) dydx=y ( yx )+x and y(1)= 3, then 2 is equal to

  1. 12
  2. 9
  3. 4
  4. 3
Ques. 5JEE Main 2024, 29 January (Evening Shift)

Let f(x)= r x \ 2r2 [(f(r))2-f(x)f(r) ]r2-x2-r3e f(r)r \ be differentiable in (- , 0) (0, ) and f(1)=1. Then the value of ea, such that f(a)=0, is equal to .

Ques. 6JEE Main 2024, 27 January (Morning Shift)

Let x=x(t) and y=y(t) be solutions of the differential equations dxdt+ax=0 and dydt+by=0 respectively, a, b . Given that x(0)=2; y(0)=1 and 3y(1)=2x(1), the value of t, for which x(t)=y(t), is :

  1. 232
  2. 432
  3. 4 3
  4. 3 4
Ques. 7JEE Main 2024, 27 January (Morning Shift)

If the solution of the differential equation (2x+3y-2) dx+(4x+6y-7) dy=0, y(0)=3, is x+ y+3 e|2x+3y- |=6, then +2 +3 is equal to .

Ques. 8JEE Main 2024, 27 January (Evening Shift)

If y=y(x) is the solution curve of the differential equation (x2-4 )dy- (y2-3y )dx=0, x>2, y(4)= 32 and the slope of the curve is never zero, then the value of y(10) equals :

  1. 31+(8)1/4
  2. 31-(8)1/4
  3. 31-2 2
  4. 31+2 2
Ques. 9JEE Main 2024, 27 January (Evening Shift)

If the solution curve, of the differential equation dydx= x+y-2x-y passing through the point (2,1) is -1 ( y-1x-1 )- 1 e ( + ( y-1x-1 )2 )= e|x-1|, then 5 + is equal to .

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