Match List - I with List - II. Choose the correct answer from the options given below :
- (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
- (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
- (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
- (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Answer
(2) (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
Solution
(A): Zn dust removes –OH: C6H5OH + Zn C6H6 + ZnO ⇒ (A) is (III)
(B): Reimer–Tiemann reaction ⇒ –CHO enters ortho ⇒ salicylaldehyde ⇒ (B) is (I)
(C): Kolbe's reaction ⇒ –COOH enters ortho ⇒ salicylic acid ⇒ (C) is (II)
(D): conc. HNO3 ⇒ 2,4,6-trinitrophenol ⇒ picric acid ⇒ (D) is (IV)
∴ (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
Answer: (2)