A string A of length 0.314 m and Young's modulus 2 1010 N/m2 is connected to another string B of length and Young's modulus both twice of those of A. This series combination of strings is then suspended from a rigid support and its free end is fixed to a load of mass 0.8 kg. The net change in length of the combination is mm. (radius of both the strings is 0.2 mm and acceleration due to gravity = 10 m/s2) (Mass of both strings is to be neglected as compared to the mass of load)
- 3
- 2
- 1.9
- 1
Answer
(2) 2
Solution
In series, both strings carry the same tension: F=mg=0.8 10=8 N
Area: A= r2= (0.2 10-3)2=4 10-8 m2
Extension: l= FLAY
String A: lA= 8 0.3144 10-8 2 1010= 2.5122512=1 10-3 m=1 mm
String B: LB=2L, YB=2Y ⇒ lB= F(2L)A(2Y)= lA=1 mm
∴ Net change in length = lA+ lB=2 mm
Answer: (2)