After passing through a polariser a linearly polarised light of intensity I is incident on an analyser making an angle of 30 with that of the polariser. The intensity of light emitted from the analyser will be
- 2I3
- I2
- I3
- 3I4
Answer
(4) 3I4
Solution
By Malus's law: I' = I 2
I' = I 2 30 = I ( 32 )2
= 3I4
Answer: (4)