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d- and f-Block Elements

JEE Main 2025 (Online) 24th January Morning ShiftMCQEasy📈 Topic in 16% papers+4−1
Ques. 1JEE Main 2025, 24 January (Morning Shift)

Preparation of potassium permanganate from MnO2 involves two step process in which the 1st step is a reaction with KOH and KNO3 to produce

  1. K3MnO4
  2. K4[Mn(OH)6]
  3. K2MnO4
  4. KMnO4

Answer

(3) K2MnO4

Solution

MnO2 + 2KOH + KNO3 K2MnO4 + KNO2 + H2O (Mn: +4 +6, green manganate)

Step 2: MnO42- MnO4- (permanganate).

Answer: (3)

Keep practising — d- and f-Block Elements

Ques. 2JEE Main 2025, 24 January (Morning Shift)

Which of the following ions is the strongest oxidizing agent? (Atomic Number of Ce = 58, Eu = 63, Tb = 65, Lu = 71)

  1. Lu3+
  2. Eu2+
  3. Tb4+
  4. Ce3+
Ques. 3JEE Main 2025, 24 January (Evening Shift)

Match List - I with List - II. Choose the correct answer from the options given below :

  1. (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  2. (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
  3. (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
  4. (A)-(IV), (B)-(II), (C)-(III), (D)-(I)
Ques. 4JEE Main 2025, 23 January (Morning Shift)

The correct set of ions (aqueous solution) with same colour from the following is:

  1. V2+, Cr3+, Mn3+
  2. Ti4+, V4+, Mn2+
  3. Sc3+, Ti3+, Cr2+
  4. Zn2+, V3+, Fe3+
Ques. 5JEE Main 2025, 23 January (Evening Shift)

Match List - I with List - II Choose the correct answer from the options given below :

  1. A-IV, B-II, C-III, D-I
  2. A-IV, B-III, C-I, D-II
  3. A-III, B-I, C-IV, D-II
  4. A-III, B-IV, C-II, D-I
Ques. 6JEE Main 2025, 23 January (Evening Shift)

Consider the following reactions K2Cr2O7 [-H2O]KOH [A] [-H2O]H2SO4 [B] + K2SO4 The products [A] and [B], respectively are :

  1. K2Cr(OH)6 and Cr2O3
  2. K2CrO4 and Cr2O3
  3. K2CrO4 and K2Cr2O7
  4. K2CrO4 and CrO
Ques. 7JEE Main 2025, 22 January (Morning Shift)

Lanthanoid ions with 4f7 configuration are : Choose the correct answer from the options given below :

  1. B and E only
  2. B and C only
  3. A and D only
  4. A and B only

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