The radius of a nucleus of mass number 64 is 4.8 fermi. Then the mass number of another nucleus having radius of 4 fermi is 1000x, where x is .
Answer
27
Solution
R = R0A1/3 A2A1 = ( R2R1 )3
A2 = 64 ( 44.8 )3 = 64 ( 56 )3
= 64 125216 = 100027
x = 27
Answer: 27