Let the set of all values of r, for which the circles (x+1)2 + (y+4)2 = r2 and x2 + y2 - 4x - 2y - 4 = 0 intersect at two distinct points be the interval ( , ). Then is equal to
- 21
- 24
- 20
- 25
Answer
(4) 25
Solution
Circle 1: centre C1(-1, -4), radius r
Circle 2: centre C2(2, 1), radius = 4 + 1 + 4 = 3
C1C2 = (2+1)2 + (1+4)2 = 34
Two distinct points of intersection:
|r - 3| < 34 < r + 3
34 - 3 < r < 34 + 3
= 34 - 3, = 34 + 3
= 34 - 9 = 25
Answer: (4)