A vessel contains 0.15 m3 of a gas at pressure 8 bar and temperature 140 °C with cp=3R and cv=2R. It is expanded adiabatically till pressure falls to 1 bar. The work done during this process is kJ. (R is gas constant)
Answer
120
Solution
= cpcv= 3R2R= 32
Adiabatic: P1V1 =P2V2
V2=V1 ( P1P2 )1/ =0.15 82/3
=0.15 4=0.6 m3
Work done by the gas: W= P1V1-P2V2 -1
= 8 105 0.15-1 105 0.60.5
= 1.2 105-0.6 1050.5=1.2 105 J
=120 kJ (the temperature 140 °C is not needed)
Answer: 120