10 mole of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from P1 to P2 is Joule (P1 = 21.7 Pa and P2 = 30 Pa, Cv = 21 J/K mol, R = 8.3 J/mol K). The value of is . [figure]
- 21
- 28
- 24
- 15
Answer
(1) 21
Solution
From the graph, the process P1 P2 takes place at constant volume V = 1 m3 (isochoric), so W = 0.
Q = nCv T
PV = nRT at constant V: n T = V PR
Q = CvRV(P2 - P1)
Q = 218.3 1 (30 - 21.7)
Q = 218.3 8.3 = 21 J
= 21
Answer: (1)