When 300 J of heat is given to an ideal gas with Cp = 72R, its temperature rises from 20 to 50 keeping its volume constant. The amount of the gas is (approximately) 10-3 mol. (R = 8.314 J/mol K)
Answer
481
Solution
Cv = Cp - R = 72R - R = 52R
At constant volume: Q = nCv T, with T = 50 - 20 = 30 K
n = QCv T = 300 52 8.314 30
n = 300623.55 = 0.481 mol
n 481 10-3 mol
Answer: 481