Let (h, k) lie on the circle C : x2 + y2 = 4 and the point (2h + 1, 3k + 2) lie on an ellipse with eccentricity e. Then the value of 5e2 is equal to .
Answer
9
Solution
Let X = 2h + 1, Y = 3k + 2
h = X - 12, k = Y - 23
h2 + k2 = 4
(X - 1)24 + (Y - 2)29 = 4
(X - 1)216 + (Y - 2)236 = 1
Major axis is vertical: a2 = 36, b2 = 16
e2 = 1 - b2a2 = 1 - 1636 = 59
5e2 = 9
Answer: 9