In the Young's double slit experiment, the intensity of light at a point on the screen where the path difference is is K, ( being the wavelength of light used). The intensity at a point where the path difference is /4 will be
- K
- K/4
- K/2
- zero
Answer
(3) K/2
Solution
I = Imax 2 2, where = 2 x
For x = : = 2 ⇒ I = Imax = K
For x = 4: = 2
I = K 2 4 = K2
Answer: (3)