2-chlorobutane + Cl2 C4H8Cl2 (isomers) Total number of optically active isomers shown by C4H8Cl2, obtained in the above reaction is .
Answer
6
Solution
Free-radical chlorination of 1CH3- 2CHCl- 3CH2- 4CH3 replaces one H (* = chiral C):
Cl at C-1: ClCH2- CHCl-CH2-CH3 ⇒ 2 (d, l)
Cl at C-2: CH3-CCl2-CH2-CH3 ⇒ 0 (no chiral C)
Cl at C-3: CH3- CHCl- CHCl-CH3 ⇒ 2 (d, l; meso form is inactive)
Cl at C-4: CH3- CHCl-CH2-CH2Cl ⇒ 2 (d, l)
∴ Optically active isomers = 2 + 0 + 2 + 2 = 6
Answer: 6