The number of real solutions of the equation x (x2+3|x|+5|x-1|+6|x-2| )=0 is .
Answer
1
Solution
x=0 or x2+3|x|+5|x-1|+6|x-2|=0
∵ every term is 0, the bracket is 0 only if x=0, x=1 and x=2 together — impossible
x2+3|x|+5|x-1|+6|x-2|>0 for all real x
only solution x=0 number of real solutions =1
Answer: 1