Two discs of same moment of inertia rotating about their regular axis passing through centre and perpendicular to the plane of disc with angular velocities 1 and 2. They are brought into contact face to face coinciding the axis of rotation. The expression for loss of energy during this process is
- 14I( 1 - 2)2
- I( 1 - 2)2
- 18I( 1 - 2)2
- 12I( 1 + 2)2
Answer
(1) 14I( 1 - 2)2
Solution
No external torque angular momentum is conserved:
I 1 + I 2 = 2I = 1 + 22
Initial KE = 12I( 12 + 22)
Final KE = 12(2I) 2 = 14I( 1 + 2)2
Loss = 12I( 12 + 22) - 14I( 1 + 2)2
= 14I( 1 - 2)2
Answer: (1)