Bag 1 contains 4 white balls and 5 black balls, and Bag 2 contains n white balls and 3 black balls. One ball is drawn randomly from Bag 1 and transferred to Bag 2. A ball is then drawn randomly from Bag 2. If the probability, that the ball drawn is white, is 2945, then n is equal to:
- 5
- 6
- 4
- 3
Answer
(2) 6
Solution
Total probability — split on the colour of the ball moved from Bag 1:
P(W)= 49 n+1n+4+ 59 nn+4= 9n+49(n+4)= 2945
⇒ 5(9n+4)=29(n+4) ⇒ 16n=96
∴ n=6
Answer: (2)