Two light beams fall on a transparent material block at point 1 and 2 with angle 1 and 2, respectively, as shown in figure. After refraction, the beams intersect at point 3 which is exactly on the interface at other end of the block. Given : the distance between 1 and 2, d = 4 3 cm and 1 = 2 = -1 ( n22n1 ), where refractive index of the block n2 > refractive index of the outside medium n1, then the thickness of the block is cm. [figure]
Answer
6
Solution
1 and 2 are measured from the surface, so the angle of incidence is i = 90 -
i = = n22n1
Snell's law: n1 i = n2 r
n1 n22n1 = n2 r r = 12, r = 30
Both beams refract at 30 to the normal and meet at point 3, so by symmetry each shifts d2 sideways.
[figure]
r = d/2t t = d2 30
t = 2 31/ 3 = 6 cm
Answer: 6