Let u and v be the distances of the object and the image from a lens of focal length f. The correct graphical representation of u and v for a convex lens when |u| > f, is
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Answer
(4) [figure]
Solution
Lens formula (u negative for a real object): 1v - 1u = 1f
v = ufu+f; with u = -|u|: v = |u|f|u|-f (positive, real image, for |u| > f)
As |u| f: v (the curve rises steeply near the dashed line |u| = f)
As |u| : v f (the curve flattens out to a small constant value)
dvd|u| = - f2(|u|-f)2 < 0, so v decreases continuously as |u| increases (rectangular hyperbola (|u|-f)(v-f) = f2).
This is shown only in graph (4).
Answer: (4)