1
Considering only the principal values of the inverse trigonometric functions, the value of -1( (-11)) + 10 (2 -1 ( 1 2 ) ) + 10 (2 -1(2)) is
- 3 + 7
- 7
- 4 + 7
- 3 - 5
Answer
(3) 4 + 7
Solution
Principal range of -1 is (0, ); (2 -1t) = 2t1 + t2.
-11 + 4 1.566 (0, ), so -1( (-11)) = 4 - 11
10 (2 4 ) = 10 2 = 10
10 (2 -12) = 10 45 = 8
Sum = 4 - 11 + 10 + 8 = 4 + 7
Answer: (C)
JEE Advanced 2026 Paper 1