If x2-y2+2hxy+2gx+2fy+c=0 is the locus of a point, which moves such that it is always equidistant from the lines x+2y+7=0 and 2x-y+8=0, then the value of g+c+h-f equals
- 8
- 14
- 29
- 6
Answer
(2) 14
Solution
Equidistant |x+2y+7| 5= |2x-y+8| 5 (locus = pair of angle bisectors)
(x+2y+7)2-(2x-y+8)2=0
-3x2+3y2+8xy-18x+44y-15=0
x2-y2- 83xy+6x- 443y+5=0 (dividing by -3)
Compare: h=- 43, g=3, f=- 223, c=5
∴ g+c+h-f=3+5- 43+ 223=14
Answer: (2)