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Inverse Trigonometric Functions · Question 2

JEE Main 2026 (Online) 6th April Morning ShiftMCQMedium📈 Topic in 16% papers+4−1
1

Let 0< <1, = 13 and -1(1- )+ -1(1- )= 4. Then 6( + ) is equal to :

  1. 6
  2. 7
  3. 8
  4. 9

Answer

(2) 7

Solution

Taking tangent of both sides :

(1- )+(1- )1-(1- )(1- )= 4=1

2- - =1-(1- - + )= + -

2( + )=2+

= 13 = 13

2( + )= 73 6( + )=7

Check : + = 76, = 13 give \ , \= \ 23, 12 \; 1- and 1- are positive with product less than 1, so the two angles really add up to 4

Answer: (2)

JEE Main 2026 (Online) 6th April Morning Shift

Keep practising — Inverse Trigonometric Functions

2

If ( -1 (x 2 ) )= ( -1 1-x2 ), x (0, 1), then the value of x is :

  1. 12
  2. 13
  3. 23
  4. 58
JEE Main 2026 (Online) 6th April Evening Shift
3

If 4+ p=111 -1 ( 2p-11+22p-1 )= , then is equal to .

JEE Main 2026 (Online) 5th April Morning Shift
4

Let [ ] denote the greatest integer function. If the domain of the function f(x)= -1 ( 4x+2[x]3 ) is [ , ], then 12( + ) is equal to :

  1. 6
  2. 8
  3. 9
  4. 4
JEE Main 2026 (Online) 4th April Morning Shift
5

If k = ( 4 + 12 -1 ( 23 ) ) + ( 12 -1 ( 23 ) ), then the number of solutions of the equation -1(kx - 1) = -1x - -1x is .

JEE Main 2026 (Online) 28th January Morning Shift
6

Considering the principal values of inverse trigonometric functions, the value of the expression (2 -1 ( 2 13 ) - 2 -1 ( 3 10 ) ) is equal to :

  1. 3356
  2. - 3356
  3. - 1663
  4. 1663
JEE Main 2026 (Online) 28th January Evening Shift
7

If the domain of the function f(x) = -1 ( 1x2 - 2x - 2 ) is (- , ] [ , ] [ , ), then + + + is equal to

  1. 4
  2. 2
  3. 5
  4. 3
JEE Main 2026 (Online) 24th January Evening Shift
8

The number of solutions of -1 4x + -1 6x = 6, where - 12 6 < x < 12 6, is equal to :

  1. 2
  2. 0
  3. 3
  4. 1
JEE Main 2026 (Online) 22nd January Morning Shift
9

If the domain of the function f(x) = -1 ( 2x - 511 - 3x ) + -1(2x2 - 3x + 1) is the interval [ , ], then + 2 is equal to :

  1. 5
  2. 2
  3. 3
  4. 1
JEE Main 2026 (Online) 21st January Morning Shift
10

Let the maximum value of ( -1x )2 + ( -1x )2 for x [- 32, 1 2 ] be mn 2, where (m, n) = 1. Then m + n is equal to .

JEE Main 2026 (Online) 21st January Evening Shift
11

The value of -1 ( 1+ 2(2)-1 (2) ) - -1 ( 1+ 2 ( 12 )+1 ( 12 ) ) is equal to

  1. - 32
  2. + 52
  3. - 54
  4. + 32
JEE Main 2025 (Online) 8th April Evening Shift

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