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Inverse Trigonometric Functions · Question 12

JEE Main 2025 (Online) 8th April Evening ShiftMCQMedium📈 Topic in 19% papers+4−1
1

The value of -1 ( 1+ 2(2)-1 (2) ) - -1 ( 1+ 2 ( 12 )+1 ( 12 ) ) is equal to

  1. - 32
  2. + 52
  3. - 54
  4. + 32

Answer

(3) - 54

Solution

2 ( 2, ) 2 < 0 1 + 2 2 = | 2| = - 2

First argument = - 2 - 1 2 = - 1 + 2 2 = - 2 2 12 1 1 = - 1

-1(- 1) = - -1( 1) = - 1 ( 1 (0, ))

12 (0, 2 ) 1 + 2 12 = 12

Second argument = 12 + 1 12 = 1 + 12 12 = 2 2 142 14 14 = 14

-1 ( 14 ) = 14

Value = - 1 - 14 = - 54

Answer: (3)

JEE Main 2025 (Online) 8th April Evening Shift

Keep practising — Inverse Trigonometric Functions

2

Considering the principal values of the inverse trigonometric functions, -1 ( 32x + 12 1 - x2 ), - 12 < x < 1 2, is equal to

  1. -5 6 - -1x
  2. 5 6 - -1x
  3. 6 + -1x
  4. 4 + -1x
JEE Main 2025 (Online) 4th April Morning Shift
3

The sum of the infinite series -1 ( 74 )+ -1 ( 194 )+ -1 ( 394 )+ -1 ( 674 )+ is :

  1. 2+ -1 ( 12 )
  2. 2- -1 ( 12 )
  3. 2- -1 ( 12 )
  4. 2+ -1 ( 12 )
JEE Main 2025 (Online) 4th April Evening Shift
4

If y = ( 3 + -1 x2 ), then (x - y)2 + 3y2 is equal to .

JEE Main 2025 (Online) 2nd April Evening Shift
5

Let S = \x : -1x = + -1x + -1(2x + 1) \. Then x S(2x - 1)2 is equal to .

JEE Main 2025 (Online) 29th January Morning Shift
6

( -1 35 + -1 513 + -1 3365 ) is equal to:

  1. 3365
  2. 1
  3. 3265
  4. 0
JEE Main 2025 (Online) 28th January Morning Shift
7

Let [x] denote the greatest integer less than or equal to x. Then the domain of f(x) = -1(2[x] + 1) is:

  1. (- , )
  2. (- , ) - \0\
  3. (- , -1] [0, )
  4. (- , -1] [1, )
JEE Main 2025 (Online) 28th January Evening Shift

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