The number of optically active products obtained from the complete ozonolysis of the given compound is : [figure]
- 4
- 0
- 2
- 1
Answer
(2) 0
Solution
Ozonolysis (O3, then Zn/H2O) breaks each C=C into two C=O groups. The three C=C bonds give:
From both ends: CH3CHO (2 molecules)
From the middle part, each stereocentre ends up between two CHO groups:
OHC- CH3 |CH-CHO (2 molecules, 2-methylpropanedial)
In 2-methylpropanedial the central carbon carries H, CH3 and two identical –CHO groups, so it is not chiral; ethanal is also achiral.
Number of optically active products = 0
Answer: (2)